Suppose we have a charge moving at velocity $\mathbf{v}$ in the same plane of a square wire.
If I sit in a reference frame where the square wire is still, since the charge is moving with velocity $\textbf{v}$ in this coordinate system, I will see an induced current in the wire.
$$\textbf{B} = \frac{\textbf{v}}{c^2} \times \textbf{E} $$ $$ \frac{d\phi_B}{dt} \neq 0 $$
Now, what If I choose a reference system where the charged particle is at its origin?
According to this frame, since the the electric charge(and its electric field) is static, $\text{rot}\,\textbf{E}$ will be zero.
$$\nabla \times\mathbf{E} = 0$$
But this means that there is no induced current.
Are my assumptions right? If not, how should I estimate the induced current in a reference system bound with a moving charge at its origin?